Chapter 7 · CBSE Class 8 Maths (NCERT Ganita Prakash Part 2)

Area

Calculate the area of quadrilaterals, triangles, and composite shapes, and apply area formulas to real-world problems.

📏 Chapter 7

7.1

Area of Quadrilaterals and Triangles

Area of a rectangle = length × breadth. Area of a triangle = ½ × base × height. Area of a parallelogram = base × height.

1

Find the area of a rectangle with length 12 cm and breadth 7 cm.

12×7 = 84 cm²

2

Find the area of a triangle with base 10 cm and height 6 cm.

½×10×6 = 30 cm²

7.2

Area of Composite Shapes

A composite shape is made of two or more simple shapes combined. Its area is found by splitting it into simple shapes, finding each area, and adding (or subtracting) them.

1

A garden is an 8m × 5m rectangle with a semicircular flower bed of radius 2.5m attached to one side. Find its total area (use π≈3.14).

Rectangle area=8×5=40 m²; semicircle area=½×3.14×2.5²=9.8125 m²; total≈49.81 m²

2

An L-shaped room is formed by a 6m×4m rectangle with a 2m×3m rectangle removed from one corner. Find its area.

6×4 − 2×3 = 24−6 = 18 m²

Practice

Exercises

1. Find the area of a rectangle with length 15 cm and breadth 9 cm.

2. Find the area of a triangle with base 14 cm and height 8 cm.

3. Find the area of a parallelogram with base 12 cm and height 5 cm.

4. A plot is a 10m×8m rectangle with a 3m×3m square pond removed. Find the remaining area.

5. A field is made of a 20m×15m rectangle joined to a right triangle with base 15m and height 6m. Find the total area.

🏆🎉 Incredible! You've completed all 14 chapters of CBSE Class 8 Ganita Prakash! 🎉🏆

From A Square and A Cube to Area — the entire Class 8 Maths book, both Part 1 and Part 2, is done. Onwards to new challenges!

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