Chapter 5 · ICSE Class 10 Mathematics (Selina Concise)

Quadratic Equations

Solve quadratic equations using factorisation and the quadratic formula, and understand the nature of roots.

🔢 Chapter 5

The parabola for x squared minus 5x plus 6 equals 0, crossing the x-axis at its two roots An upward-opening parabola dipping below the x-axis between x=2 and x=3, the two roots of the equation x squared minus 5x plus 6 equals 0, since the expression is negative between its roots x = 2 x = 3 x² − 5x + 6 = 0 → (x−2)(x−3) = 0
5.1

Solving by Factorisation

A quadratic equation ax²+bx+c=0 can be solved by factorising into two linear factors, if possible.

1

Solve: x²−5x+6=0

(x−2)(x−3)=0; x=2 or x=3

2

Solve: x²+3x−10=0

(x+5)(x−2)=0; x=−5 or x=2

5.2

The Quadratic Formula

x=[−b±√(b²−4ac)]/2a solves any quadratic equation. The discriminant b²−4ac tells us the nature of the roots.

1

Solve x²+2x−8=0 using the quadratic formula.

x=[−2±√(4+32)]/2=[−2±6]/2; x=2 or x=−4

2

Find the discriminant of 2x²−4x+2=0 and describe the roots.

D=16−16=0; equal (repeated) real roots

Practice

Exercises

1. Solve by factorisation: x²−7x+12=0

2. Solve by factorisation: x²−x−6=0

3. Solve using the formula: x²−4x+1=0

4. Find the discriminant of x²+6x+9=0 and describe the roots.

5. Find the discriminant of x²+x+1=0 and describe the roots.