Chapter 22 · ICSE Class 8 Mathematics

Area of a Trapezium and a Polygon

Learn to find the area of trapeziums and other irregular polygons by splitting them into familiar shapes.

🔺 Chapter 22

The area of a trapezium with parallel sides 10 and 6, and height 4 A trapezium with two parallel sides of length 10 and 6, and a height of 4 between them, used to calculate the area as half the sum of the parallel sides times the height, giving 32 10 6 h=4 Area = ½(10+6)×4 = 32
22.1

Area of a Trapezium

A trapezium has one pair of parallel sides. Its area is found using: Area = ½ × (sum of parallel sides) × height, where height is the perpendicular distance between the parallel sides.

1

A trapezium has parallel sides 10cm and 6cm, with a height of 4cm. Find its area.

½ × (10+6) × 4 = ½ × 16 × 4 = 32 square cm

2

A trapezium has parallel sides 12cm and 8cm, with a height of 5cm. Find its area.

½ × (12+8) × 5 = ½ × 20 × 5 = 50 square cm

22.2

Area of an Irregular Polygon

An irregular polygon can be split into triangles and trapeziums (or rectangles), and the total area found by adding up each piece's area separately.

1

A polygon is split into a triangle (area 20 sq cm) and a trapezium (area 35 sq cm). Find the total area.

20 + 35 = 55 square cm

2

An irregular pentagon is split into 3 triangles with areas 12, 18, and 15 square cm. Find its total area.

12 + 18 + 15 = 45 square cm

Practice

Exercises

1. A trapezium has parallel sides 14cm and 10cm, with a height of 6cm. Find its area.

2. A trapezium has parallel sides 20cm and 12cm, with a height of 7cm. Find its area.

3. A trapezium has an area of 60 sq cm, parallel sides 15cm and 9cm. Find its height.

4. A polygon is split into a rectangle (area 40 sq cm) and a triangle (area 15 sq cm). Find its total area.

5. An irregular quadrilateral is split by a diagonal into two triangles with areas 24 and 18 square cm. Find its total area.