Chapter 7 · ICSE Class 9 Chemistry (Selina Concise)

Study of Gas Laws

How the volume of a gas changes with pressure and temperature, and what STP means.

🎚️ Chapter 7

Boyle and Charles laws Left a hyperbola showing volume falling as pressure rises at constant temperature; right a straight line through zero kelvin showing volume rising with temperature at constant pressure. Pressure P (atm) V Boyle: P × V = constant 2 atm → 3 L (PV = 6) Temperature T (K) V Charles: V ∝ T (kelvin) 0 K 27 °C = 300 K; heated to 127 °C = 400 K, so 300 mL becomes 400 mL. K = °C + 273.

↔ Swipe the diagram sideways to see all of it

7.1

Boyle's law

Gas particles move randomly and far apart, so a gas has no fixed shape or volume. Boyle's law: at constant temperature the volume of a fixed mass of gas is inversely proportional to its pressure, so PV = constant and P₁V₁ = P₂V₂. A graph of V against P is a curve (hyperbola); V against 1/P is a straight line.

1

A gas occupies 6 L at 1 atm. Find its volume at 3 atm (constant temperature).

V₂ = P₁V₁ ÷ P₂ = 1 × 6 ÷ 3 = 2 L.

2

What happens to the volume when the pressure is halved?

It doubles.

3

Why does a bicycle pump get hard to push?

Compressing the air raises its pressure as the volume falls.

7.2

Charles' law and the kelvin scale

Charles' law: at constant pressure the volume of a fixed mass of gas is directly proportional to its absolute temperature, V₁/T₁ = V₂/T₂. Absolute temperature in kelvin = °C + 273, and 0 K (−273 °C) is the lowest possible temperature. Always convert to kelvin before using the law.

1

300 mL of gas at 27 °C is heated to 127 °C at constant pressure. Find the new volume.

T₁ = 300 K, T₂ = 400 K. V₂ = 300 × 400 ÷ 300 = 400 mL.

2

Convert 0 °C, 100 °C and −273 °C to kelvin.

273 K, 373 K and 0 K.

3

Why can the Celsius temperature not be used directly in V₁/T₁ = V₂/T₂?

At 0 °C the volume is not zero, so volume is not proportional to °C; it is proportional to kelvin.

7.3

Standard temperature and pressure

Gas volumes depend on temperature and pressure, so they are compared at standard temperature and pressure: 0 °C (273 K) and 760 mm Hg (1 atm). To convert a volume to STP, combine both laws: V₀ = V × (P ÷ 760) × (273 ÷ T). At STP one mole of any gas occupies 22.4 L.

1

Convert 500 mL of gas at 27 °C and 750 mm Hg to STP.

V₀ = 500 × 750 ÷ 760 × 273 ÷ 300 = 449.01 mL.

2

State STP values.

273 K (0 °C) and 760 mm Hg (1 atm).

3

Which law explains why a sealed balloon shrinks in a freezer?

Charles' law: lower temperature reduces the volume at constant pressure.

Practice

Exercises

1. State Boyle's law.

2. State Charles' law.

3. Convert 47 °C to kelvin.

4. A gas has volume 10 L at 2 atm. Find the volume at 5 atm.

5. 300 mL of a gas at 300 K is cooled to 150 K. Find the volume.

6. What is absolute zero?

7. Give the values of STP.

8. What volume does 1 mole of oxygen occupy at STP?

9. Why must temperature be in kelvin in gas calculations?

10. The pressure on 6 L of gas is doubled at constant temperature. State the new volume.

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