Chapter 16 · ICSE Class 7 Mathematics

Pythagoras Theorem

Discover the famous relationship between the sides of a right triangle, and use it to find missing lengths.

📏 Chapter 16

The Pythagoras theorem verified on a 3-4-5 right triangle A right triangle with legs 3 and 4 and hypotenuse 5, alongside three separate squares showing their areas 9, 16, and 25, demonstrating that the sum of the areas on the two legs equals the area on the hypotenuse 3 4 5 3²=9 4²=16 5²=25 3² + 4² = 5² → 9 + 16 = 25
16.1

Statement of the Pythagoras Theorem

In a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) equals the sum of the squares of the other two sides: (hypotenuse)² = (side 1)² + (side 2)².

1

A right triangle has legs of 3cm and 4cm. Find the hypotenuse.

3² + 4² = 9 + 16 = 25, so hypotenuse = √25 = 5cm

2

A right triangle has legs of 6cm and 8cm. Find the hypotenuse.

6² + 8² = 36 + 64 = 100, so hypotenuse = √100 = 10cm

16.2

Finding a Missing Leg

If the hypotenuse and one leg are known, the other leg can be found by rearranging the theorem: (leg)² = (hypotenuse)² − (other leg)².

1

A right triangle has a hypotenuse of 13cm and one leg of 5cm. Find the other leg.

13² − 5² = 169 − 25 = 144, so the leg = √144 = 12cm

2

A ladder 10m long leans against a wall, with its base 6m from the wall. How high up the wall does it reach?

10² − 6² = 100 − 36 = 64, so the height = √64 = 8m

Practice

Exercises

1. A right triangle has legs of 5cm and 12cm. Find the hypotenuse.

2. A right triangle has legs of 9cm and 12cm. Find the hypotenuse.

3. A right triangle has a hypotenuse of 17cm and one leg of 8cm. Find the other leg.

4. A right triangle has a hypotenuse of 25cm and one leg of 7cm. Find the other leg.

5. A rectangular field is 12m long and 5m wide. Find the length of its diagonal.